Amp/Component Help : am i at 2 or 4 Ohm ?
hey i have a pair of infinity perfect 6.1 in the front doors...i have them hooked to a elemental designs nine.2 amp... its rated at
100 x 2 at 4ohm
150 X 2 at 2 ohm
400 X 1 at 2 ohm
my question is, my comps are 4 ohm inpedance, how do i put them to a 2 ohm load, this ____tey pic shows how i have it set up ( 1 cross to channel 1, 1 cross to channel 2) that is 4ohm load right ? i just dont think im gettin the full potential
... and i dont want to bridge to 1 channel and push over 400 w to the comps ( thats there max)
someone please let me know if i can make this a 2 ohm load
thanks
100 x 2 at 4ohm
150 X 2 at 2 ohm
400 X 1 at 2 ohm
my question is, my comps are 4 ohm inpedance, how do i put them to a 2 ohm load, this ____tey pic shows how i have it set up ( 1 cross to channel 1, 1 cross to channel 2) that is 4ohm load right ? i just dont think im gettin the full potential
... and i dont want to bridge to 1 channel and push over 400 w to the comps ( thats there max)
someone please let me know if i can make this a 2 ohm load
thanks
if you put a 4 ohm resistor in parallel with the crossovers, that would give you 2ohm load at the amp, but I don't know how the resistors would act with the extra power..(they might take half of the power going to the components per side and turn it into heat)
Keep in mind, that if you run an amp at a 2ohm load, instead of a 4ohm, you're going to see more power, but also increased distortion. there is always a trade off.
If you want to get that amp to run at 2 ohms, buy another set of the same comps. Remember, ohms are determined at a given frequency. That's why a set of comp's sees a four ohm load: the woofer and tweeter are operating at seperate freq's.
If you want to get that amp to run at 2 ohms, buy another set of the same comps. Remember, ohms are determined at a given frequency. That's why a set of comp's sees a four ohm load: the woofer and tweeter are operating at seperate freq's.
Originally Posted by SCI_TC_GUY
if you put a 4 ohm resistor in parallel with the crossovers, that would give you 2ohm load at the amp, but I don't know how the resistors would act with the extra power..(they might take half of the power going to the components per side and turn it into heat)
Nine.4 bridged at 4 actually gets a bit over 200...we had to bench one the other day.
Or...wait for a Nine.2X...200x2 at 4ohms, 400x2 at 2 ohms, chassis of the Nine.1..probably around August.
Or...wait for a Nine.2X...200x2 at 4ohms, 400x2 at 2 ohms, chassis of the Nine.1..probably around August.
Originally Posted by mandos
Nine.4 bridged at 4 actually gets a bit over 200...we had to bench one the other day.
Or...wait for a Nine.2X...200x2 at 4ohms, 400x2 at 2 ohms, chassis of the Nine.1..probably around August.
Or...wait for a Nine.2X...200x2 at 4ohms, 400x2 at 2 ohms, chassis of the Nine.1..probably around August.
Originally Posted by SuperCrunchyAction
Originally Posted by mandos
Nine.4 bridged at 4 actually gets a bit over 200...we had to bench one the other day.
Or...wait for a Nine.2X...200x2 at 4ohms, 400x2 at 2 ohms, chassis of the Nine.1..probably around August.
Or...wait for a Nine.2X...200x2 at 4ohms, 400x2 at 2 ohms, chassis of the Nine.1..probably around August.
Bridged Nine.4 on a set of 6500s is unbearable at high volumes...but horribly clear ;)
Originally Posted by mandos
Originally Posted by SuperCrunchyAction
Originally Posted by mandos
Nine.4 bridged at 4 actually gets a bit over 200...we had to bench one the other day.
Or...wait for a Nine.2X...200x2 at 4ohms, 400x2 at 2 ohms, chassis of the Nine.1..probably around August.
Or...wait for a Nine.2X...200x2 at 4ohms, 400x2 at 2 ohms, chassis of the Nine.1..probably around August.
Bridged Nine.4 on a set of 6500s is unbearable at high volumes...but horribly clear ;)
Originally Posted by SuperCrunchyAction
Originally Posted by SCI_TC_GUY
if you put a 4 ohm resistor in parallel with the crossovers, that would give you 2ohm load at the amp, but I don't know how the resistors would act with the extra power..(they might take half of the power going to the components per side and turn it into heat)
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