View Full Version : Calc anyone?


a_german_named_hans
02-17-2009, 04:41 PM
Having a hell of a time figuring this one out.

2*Pi (Integral)(x*(1/(sqrt(x+1))),x); from 0 to 1.

so it looks kinda like

2 Pi (Integral bs) x * ____1___
------------------------sqrt(x+1)

disregard the ---- they're just there to have the thing under the 1

anyone?

natural log maybe?

senseiturtle
02-17-2009, 05:07 PM
KILL IT WITH FIRE!

a_german_named_hans
02-17-2009, 05:11 PM
^^ I tried that already, fire alarms started going off, just didn't turn out well.

davedavetC
02-17-2009, 05:13 PM
lol it took me 4 semesters to pass calc, i hate it.... a lot

a_german_named_hans
02-17-2009, 05:30 PM
figured it out. Answer is

2 * Pi * (1/(2*sqrt(x+1))*(4*sqrt(x+1))/3)

fun isn't it?

andino
02-18-2009, 01:24 AM
haha indefinate integrals are fun stuff. You need to do chain rule to figure it out

edit: Oops i didn't see the bounds