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Old Feb 17, 2009 | 04:41 PM
  #1  
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Default Calc anyone?

Having a hell of a time figuring this one out.

2*Pi (Integral)(x*(1/(sqrt(x+1))),x); from 0 to 1.

so it looks kinda like

2 Pi (Integral bs) x * ____1___
------------------------sqrt(x+1)

disregard the ---- they're just there to have the thing under the 1

anyone?

natural log maybe?
Old Feb 17, 2009 | 05:07 PM
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KILL IT WITH FIRE!
Old Feb 17, 2009 | 05:11 PM
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^^ I tried that already, fire alarms started going off, just didn't turn out well.
Old Feb 17, 2009 | 05:13 PM
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lol it took me 4 semesters to pass calc, i hate it.... a lot
Old Feb 17, 2009 | 05:30 PM
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figured it out. Answer is

2 * Pi * (1/(2*sqrt(x+1))*(4*sqrt(x+1))/3)

fun isn't it?
Old Feb 18, 2009 | 01:24 AM
  #6  
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haha indefinate integrals are fun stuff. You need to do chain rule to figure it out

edit: Oops i didn't see the bounds
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